If \( 2A \times A = B2A \), where A and B are digits, then which of the following is correct?

English বাংলা
PREVIOUSLY ASKED IN:
CTET 2026

Answer

\( A=5, B=1 \)

Explanation

Since \( A \times A \) ends with the digit \( A \), A can be 1, 5, or 6. If we take \( A = 5 \), then \( 25 \times 5 = 125 \), which matches the \( B2A \) format perfectly (with \( B = 1 \) and the tens digit being 2). If \( A = 6 \), then \( 26 \times 6 = 156 \), but the tens digit is 5, not 2. Therefore, \( A=5, B=1 \) is the correct answer.

Key Points

  • > In such alphametic puzzles, begin by analyzing the units digit logic.
  • > Digits whose squares end in themselves are 0, 1, 5, and 6.
  • > If \( A = 1 \), \( 21 \times 1 = 21 \), which does not yield a 3-digit number like B2A.
  • > For \( A = 5 \), the tens digit of its square is always 2 (e.g., 25, 225).
  • > These puzzles are highly effective for improving logical reasoning and number sense.
  • > Option testing is a very quick method to solve these in an exam setup.
  • > This is a frequent pattern in CTET and other competitive exams.

Additional Information

Cryptarithmetic Puzzle Analysis

Digit (A)EquationResultRemark
121 × 121Not a 3-digit number
525 × 5125B=1, Tens digit 2 (Correct)
626 × 6156Tens digit is 5 (Wrong)
929 × 9261Ends in 1, not A

Memory Tips

  • Square Property: The squares of numbers ending in 5 or 6 always end with the same digit.
  • Option Test Approach: Instead of creating complex equations, simply plug in the given options to find the correct match.
Mathematics Number System Medium