Answer
12 days
Explanation
A's one day work is \( \frac{1}{20} \), B's one day work is \( \frac{1}{30} \). Combined one day work is \( \frac{1}{20} + \frac{1}{30} = \frac{3+2}{60} = \frac{5}{60} = \frac{1}{12} \). Thus, they will finish the work together in 12 days.
Key Points
- > Combined time \( = \frac{xy}{x+y} \)
- > Here \( x = 20 \) and \( y = 30 \)
- > Time and work capacity are inversely proportional
Additional Information
- It is often easier to assume the total work as the Least Common Multiple (LCM).
- LCM of \( 20, 30 = 60 \) units.
- A's efficiency = 3 units/day, B's efficiency = 2 units/day.
| Method | Explanation |
|---|---|
| LCM Method | Divide total work by efficiency |
| Fraction Method | Add daily work rates |
